0.004x^2+0.62x=0

Solution for 0.004x^2+0.62x=0 equation:

0.004x^2+0.62x=0

a = 0.004; b = 0.62; c = 0;
Δ = b2-4ac
Δ = 0.622-4·0.004·0
Δ = 0.3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.62)-\sqrt{0.3844}}{2*0.004}=\frac{-0.62-\sqrt{0.3844}}{0.008}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.62)+\sqrt{0.3844}}{2*0.004}=\frac{-0.62+\sqrt{0.3844}}{0.008}
$